11b^2-4=40

Solution for 11b^2-4=40 equation:

11b^2-4=40

We move all terms to the left:

11b^2-4-(40)=0

We add all the numbers together, and all the variables

11b^2-44=0

a = 11; b = 0; c = -44;
Δ = b2-4ac
Δ = 02-4·11·(-44)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-44}{2*11}=\frac{-44}{22}
=-2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+44}{2*11}=\frac{44}{22}
=2
$